(2b-1)(b^2-3b+4)=0

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Solution for (2b-1)(b^2-3b+4)=0 equation:


Simplifying
(2b + -1)(b2 + -3b + 4) = 0

Reorder the terms:
(-1 + 2b)(b2 + -3b + 4) = 0

Reorder the terms:
(-1 + 2b)(4 + -3b + b2) = 0

Multiply (-1 + 2b) * (4 + -3b + b2)
(-1(4 + -3b + b2) + 2b * (4 + -3b + b2)) = 0
((4 * -1 + -3b * -1 + b2 * -1) + 2b * (4 + -3b + b2)) = 0
((-4 + 3b + -1b2) + 2b * (4 + -3b + b2)) = 0
(-4 + 3b + -1b2 + (4 * 2b + -3b * 2b + b2 * 2b)) = 0
(-4 + 3b + -1b2 + (8b + -6b2 + 2b3)) = 0

Reorder the terms:
(-4 + 3b + 8b + -1b2 + -6b2 + 2b3) = 0

Combine like terms: 3b + 8b = 11b
(-4 + 11b + -1b2 + -6b2 + 2b3) = 0

Combine like terms: -1b2 + -6b2 = -7b2
(-4 + 11b + -7b2 + 2b3) = 0

Solving
-4 + 11b + -7b2 + 2b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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